leetcodeday68 –文本左右对齐

给定一个单词数组和一个长度 maxWidth，重新排版单词，使其成为每行恰好有 maxWidth 个字符，且左右两端对齐的文本。

你应该使用“贪心算法”来放置给定的单词；也就是说，尽可能多地往每行中放置单词。必要时可用空格 ' ' 填充，使得每行恰好有 maxWidth 个字符。

要求尽可能均匀分配单词间的空格数量。如果某一行单词间的空格不能均匀分配，则左侧放置的空格数要多于右侧的空格数。

文本的最后一行应为左对齐，且单词之间不插入额外的空格。

说明:

• 单词是指由非空格字符组成的字符序列。
• 每个单词的长度大于 0，小于等于 maxWidth。
• 输入单词数组 words 至少包含一个单词。

示例:

输入:
words = ["This", "is", "an", "example", "of", "text", "justification."]
maxWidth = 16
输出:
[
   "This    is    an",
   "example  of text",
   "justification.  "
]

示例 2:

输入:
words = ["What","must","be","acknowledgment","shall","be"]
maxWidth = 16
输出:
[
  "What   must   be",
  "acknowledgment  ",
  "shall be        "
]
解释: 注意最后一行的格式应为 "shall be    " 而不是 "shall     be",
     因为最后一行应为左对齐，而不是左右两端对齐。       
     第二行同样为左对齐，这是因为这行只包含一个单词。

示例 3:

输入:
words = ["Science","is","what","we","understand","well","enough","to","explain",
         "to","a","computer.","Art","is","everything","else","we","do"]
maxWidth = 20
输出:
[
  "Science  is  what we",
  "understand      well",
  "enough to explain to",
  "a  computer.  Art is",
  "everything  else  we",
  "do                  "
]

code：

# [68] 文本左右对齐
#

# @lc code=start
class Solution:
    def fullJustify(self, words: List[str], maxWidth: int) -> List[str]:
        lens=len(words)
        rev=list()
        nowlens=0
        start=0
        i=0
        while i<lens:
            wordlen=len(words[i])
            nowlens=nowlens+wordlen
            #print(i,nowlens)
            if nowlens<maxWidth:
                nowlens+=1
                i=i+1
                #print(i)
                #print(nowlens)
            elif nowlens>maxWidth:
                nowlens=nowlens-wordlen-1
                
                reslens=maxWidth-nowlens
                m=(i-1-start)
                if m==0:
                    mid=""
                    mid=mid+words[start]+(maxWidth-len(words[start]))*" "
                    rev.append(mid)
                #print(reslens,reslens//(i-1-start),reslens/(i-1-start))
                elif reslens//(i-1-start)==reslens/(i-1-start):
                    mid=""
                    x=reslens//(i-1-start)+1
                    for j in range(start,i-1):
                        mid=mid+words[j]+x*" "
                    mid=mid+words[i-1]
                    rev.append(mid)
                else:
                    other=reslens%(i-1-start)
                    mid=""
                    x=reslens//(i-1-start)+1
                    print(x,other)
                    for j in range(start,i-1):
                        if other>0:
                            mid=mid+words[j]+x*" "+" "
                            other-=1
                        else:
                            mid=mid+words[j]+x*" "
                    mid=mid+words[i-1]
                    rev.append(mid)
                nowlens=0
                start=i
            elif nowlens==maxWidth:
                mid=""
                for j in range(start,i):
                    mid=mid+words[j]+" "
                mid=mid+words[i]
                rev.append(mid)
                start=i+1
                nowlens=0
                i=i+1
        if start<lens:
            mid=""
            for j in range(start,lens):
                mid=mid+words[j]+" "
            mid=mid[:-1]
            other=maxWidth-len(mid)
            mid=mid+other*" "
            rev.append(mid)
        return rev    
                
             
# @lc code=end